The points (k + 1, 1), (2k + 1, 3) and (2k + 2, 2k) are collinear ifa)k = - 1, 2b)c)k = 2, 1d)Correct answer is option 'D'. Can you explain this answer? - EduRev Class 10 Question
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2.If the points (k, 2 2k), ( k+1, 2k) and ( 4 k, 6 2k) are collinear, then k=1(b)2(a) 1(d)2(c)
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![b) Find the value of k which the roots of following equation are real & equal k2x2 -2(2k-1)x + 4 = 0 AC-AB & ABC = 720DA& B are the two tangents. [3]](https://toppr-doubts-media.s3.amazonaws.com/images/3421266/91af8e67-ba54-4d28-914b-497183b2b95b.jpg "b) Find the value of k which the roots of following equation are real & equal k2x2 -2(2k-1)x + 4 = 0 AC-AB & ABC = 720DA& B are the two tangents. [3]")
b) Find the value of k which the roots of following equation are real & equal k2x2 -2(2k-1)x + 4 = 0 AC-AB & ABC = 720DA& B are the two tangents. [3]
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Halmazok. Legyen A={a; a=4k 2 -2k+1; kЄ N} – Legyen B={b; b=(8m 3 +1)/(4m 2 -2m+1), m ЄN} – Adja meg az A halmaz elemeit k=1,3,5,7-re, a B halmaz elemeit. - ppt
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